What Speed and Direction Does the Tangled Metal Move Post-Collision?

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SUMMARY

The collision of two cars, one with a mass of 1680 kg traveling northeast at 14 m/s and another with a mass of 1300 kg traveling south at 13 m/s, results in a combined mass moving post-collision. The conservation of momentum equation m1v1i + m2v2i = v1(m1 + m2) is applicable, but must be separated into x and y components due to the vector nature of momentum. The correct approach involves calculating the momentum in both directions to determine the speed and direction of the tangled mass immediately after the collision.

PREREQUISITES
  • Understanding of vector quantities in physics
  • Familiarity with conservation of momentum principles
  • Basic knowledge of trigonometry for angle calculations
  • Ability to resolve forces into components
NEXT STEPS
  • Calculate momentum components for both cars before the collision
  • Learn how to resolve vectors into x and y components
  • Study examples of inelastic collisions in physics
  • Explore the concept of momentum conservation in two dimensions
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Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators looking for practical examples of momentum conservation in real-world scenarios.

aquirk
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Homework Statement


A car with a mass of 1680 kg is traveling directly northeast (45° between north and east) at a speed of 14 m/s (31 mph), and collides with a smaller car with a mass of 1300 kg that is traveling directly south at a speed of 13 m/s (29 mph). The two cars stick together during the collision. With what speed and direction does the tangled mess of metal move right after the collision?
Magnitude __________ m/s
Direction _________ degrees South of east


Homework Equations


m1v1i+m2v2i = v1(m1+m2)



The Attempt at a Solution


i tried plugging my values into this equation to figure out the answer but it doesn't seem to give me the right answer. I am thinking maybe I am doing it wrong because there is an angle involved but I am not sure.
 
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aquirk said:

Homework Statement


A car with a mass of 1680 kg is traveling directly northeast (45° between north and east) at a speed of 14 m/s (31 mph), and collides with a smaller car with a mass of 1300 kg that is traveling directly south at a speed of 13 m/s (29 mph). The two cars stick together during the collision. With what speed and direction does the tangled mess of metal move right after the collision?
Magnitude __________ m/s
Direction _________ degrees South of east


Homework Equations


m1v1i+m2v2i = v1(m1+m2)



The Attempt at a Solution


i tried plugging my values into this equation to figure out the answer but it doesn't seem to give me the right answer. I am thinking maybe I am doing it wrong because there is an angle involved but I am not sure.


You're on the right track using conservation of momentum, but you seem to have forgotten that momentum is a vector quantity and therefore you will have an equation for the x-components and an equation fro the y-components. So, yes you need to make use of the angle.
 

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