What Speed and Direction Does the Tangled Metal Move Post-Collision?

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aquirk
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Homework Statement


A car with a mass of 1680 kg is traveling directly northeast (45° between north and east) at a speed of 14 m/s (31 mph), and collides with a smaller car with a mass of 1300 kg that is traveling directly south at a speed of 13 m/s (29 mph). The two cars stick together during the collision. With what speed and direction does the tangled mess of metal move right after the collision?
Magnitude __________ m/s
Direction _________ degrees South of east


Homework Equations


m1v1i+m2v2i = v1(m1+m2)



The Attempt at a Solution


i tried plugging my values into this equation to figure out the answer but it doesn't seem to give me the right answer. I am thinking maybe I am doing it wrong because there is an angle involved but I am not sure.
 
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aquirk said:

Homework Statement


A car with a mass of 1680 kg is traveling directly northeast (45° between north and east) at a speed of 14 m/s (31 mph), and collides with a smaller car with a mass of 1300 kg that is traveling directly south at a speed of 13 m/s (29 mph). The two cars stick together during the collision. With what speed and direction does the tangled mess of metal move right after the collision?
Magnitude __________ m/s
Direction _________ degrees South of east


Homework Equations


m1v1i+m2v2i = v1(m1+m2)



The Attempt at a Solution


i tried plugging my values into this equation to figure out the answer but it doesn't seem to give me the right answer. I am thinking maybe I am doing it wrong because there is an angle involved but I am not sure.


You're on the right track using conservation of momentum, but you seem to have forgotten that momentum is a vector quantity and therefore you will have an equation for the x-components and an equation fro the y-components. So, yes you need to make use of the angle.