What Speed Does the Athlete Land in Long Jump?

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Homework Help Overview

The problem involves a long jump scenario where an athlete jumps at an angle of 25 degrees and lands 8.8 meters away from the launch point, with both points at the same height. The focus is on determining the speed at which the athlete lands.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the range formula and its application to find the initial velocity needed to solve for the landing speed. Questions arise about understanding and manipulating the formula correctly.

Discussion Status

Some participants are exploring the range formula and its rearrangement to find initial velocity. There is an acknowledgment of confusion regarding the calculations, and some guidance is offered on how to manipulate the formula. Multiple interpretations of the problem are being explored.

Contextual Notes

Participants express uncertainty about the range formula and its components, indicating a need for clarification on the initial velocity and its calculation. There is mention of difficulties in obtaining a suitable numerical result.

zman2011
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Homework Statement


During a high school track meet, an athlete performing the long jump runs and leaps at an angle of 25 degrees and lands in a sand pit 8.8 m from his launching point. If the launch point and landing point are at the same height, y=0m, with what apeed does the athlete land?



Homework Equations





The Attempt at a Solution


Im completely stumped. any help would be appreciated.
 
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Are you familiar with the range formula?
 
no i am not.
 
can anyone tell me what the range formula is?
 
R = ((v0)2 sin(2\theta0)) / g

Rearranging this formula and solving for v0 will give you the initial velocity. You can figure out the final velocity from there.
 
well then how do i find initial velocity to put it in.
 
i didnt see the second part of that. sorry. thank you
 
im having trouble with this. i keep getting initial velocity as a decimal
 
Maybe you aren't substituting/manipulating properly.

x = \frac{v_o^2sin2\theta}{g}
v_o=\sqrt{\frac{xg}{sin2\theta}}
 

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