What Strategies Can Tackle This Complex Contour Integral?

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Homework Help Overview

The discussion revolves around a complex contour integral involving trigonometric functions and exponential terms. Participants are exploring strategies to tackle the integral, particularly focusing on the implications of having a cosine term in the denominator.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster expresses difficulty with the integral due to the cosine in the denominator and seeks hints or help. Some participants question the validity of the expression, specifically the presence of the cosine term. Others share their own related expressions and transformations, indicating attempts to simplify or reinterpret the problem.

Discussion Status

The discussion is ongoing, with participants sharing their thoughts and questioning the setup of the integral. There is a recognition of potential errors in the expressions provided, and some participants are revising their earlier statements to clarify their reasoning.

Contextual Notes

There are indications of confusion regarding the formulation of the integral, with participants reflecting on their assumptions and the transformations they have applied. The nature of the problem suggests that additional context or constraints may be influencing the discussion.

MadMax
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Contour integral

How would you deal with this?

[tex]\int \frac{\rho \sin{\theta} d \rho d \theta}{\cos{\theta}} \frac{K^2}{K^2 + \rho^2} e^{i \rho \cos{\theta} f(\mathbf{x})}[/tex]

if the cos(theta) were'nt on the bottom I'd have no problem; I'd simply substitute for cos(theta) and the sin(theta) would cancel...

but as it stands.. I'm stumped.

Help/hints would be much appreciated. Thanks for reading.
 
Last edited:
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Are you sure there should be a cos(theta) in the denominator? Where did that expression come from?
 
well I had something like:

[tex]\int \frac{d^3 \mathbf{q}}{\mathbf{q_z}} \frac{2K^2 + \mathbf{q}^2 - (\mathbf{q} \cdot \hat{x})^2}{2(K^2 + \mathbf{q}^2)}e^{i \mathbf{q_{\perp}} \cdot \mathbf{x}}e^{i \mathbf{q_z} f(\mathbf{x})}[/tex]

I made q_z parallel to x, (which means the first exponential disappears), converted into spherical coords, integrated over \phi from 0 to 2pi, and thus...
 
Last edited:
I guess I'm stumped as well. Anybody else seen something like that?
 
I wasn't correct in some of the things I wrote in the two equations. The second exponential in particular...

I edited them so they're correct now. Not sure if it makes a difference but perhaps it helps? Might make sense how I got from one to the other now anyway...
 

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