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What units are used after eV, MeV, GeV, etc, are divided by c^2?

  1. Feb 16, 2011 #1
    I know that the mass of subatomic particles is usually given in electronvolts, and that c[tex]^{2}[/tex] is set to 1 so that we can say, "This particle has a mass of 13 eV." However, if you divide 13 eV by c[tex]^{2}[/tex], you get an answer, x. What units is this in?

    Oh, also, what units do we use c in in the first place? km/s, m/s, mi/s?
     
  2. jcsd
  3. Feb 16, 2011 #2

    Drakkith

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    Staff: Mentor

    I believe it is Kilograms or grams since that is the unit of mass. Cant say for the c.
     
  4. Feb 16, 2011 #3

    jtbell

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    This is sloppy language which is unfortunately commonly used by physicists.

    The electron-volt (eV) is a unit of energy, equal to 1.602e-19 joule.

    When someone says "the mass of an electron is 511 keV" he really means, "the energy-equivalent of the mass of an electron is 511 keV" or "the rest-energy of an electron is 511 keV" or "the mass of an electron is 511 keV/c^2." Mathematically,

    [tex]m_e c^2 = 511 \rm{ keV}[/tex]

    Dividing through by c^2 we get

    [tex]m_e = 511 \rm{ keV}/c^2[/tex]

    so the eV/c^2 is a unit of mass, equal to (1.602e-19 J)/(2.998e8 m/s)^2 = 1.782e-36 kg.

    To check this, 511 keV = 511 x 1000 x 1.782e-36 kg = 9.108e-31 kg which is indeed the mass of an electron in kg.
     
    Last edited: Feb 16, 2011
  5. Feb 17, 2011 #4

    clem

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    This language is fortunately commonly used by physicists.
    There are several systems of units in which c=1 and is dimensionless.
    (Distance in light-years and time in years is one.)
    All of those systems are more useful than kg or joules in describing an electron.
     
  6. Feb 17, 2011 #5

    jtbell

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    I wouldn't call "light-years per year" dimensionless.
     
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