What values of k make x^2 + 12x + k factorable over the integers?

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The discussion focuses on identifying the positive values of k that make the quadratic expression x² + 12x + k factorable over the integers. It is established that for the expression to be factorable, the discriminant must be a perfect square. The discriminant, calculated as 12² - 4k, leads to the condition that 144 - 4k must equal n² for some integer n. This results in the conclusion that k can take on specific values such as 1, 4, 9, 16, 25, 36, 49, 64, 81, and 100, corresponding to perfect squares of integers.

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try to determine all the positive values of k for which x^2 + 12x + k is factorable over the integers.
 
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Here's my solution:

Set $x^{2}+12x+k=(x+a)(x+b)=x^{2}+(a+b)x+k.$
Evidently, then, the values of $k$ are products of numbers whose sum is $12$. The possibilities are as follows:
\begin{align*}
1+11=12& \to k=11\\
2+10=12& \to k=20\\
3+9=12& \to k=27\\
4+8=12& \to k=32\\
5+7=12& \to k=35\\
6+6=12& \to k=36.
\end{align*}
Then they repeat.
 

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