What Vertical Velocity Is Needed for a Slam Dunk?

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SUMMARY

The discussion centers on calculating the vertical velocity component required for a basketball player to achieve a slam dunk from a jump height of 1 meter. The player approaches the basket at a horizontal velocity of 6 m/s. The calculations confirm that using gravitational acceleration (g = 9.81 m/s²), the vertical velocity needed is approximately 4.43 m/s. Additionally, the horizontal distance from the basket for the jump is determined to be 2.71 meters, based on the time taken to reach maximum height.

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chris_0101
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1. Homework Statement [/b

A basketball player is approaching the basket at a velocity of 6m/s when he jumps into the air to perform a slam dunk. Calculate the vertical velocity component required to lift the player 1m above the ground. Determine the distance from the basket needed for the start of the jump in order for the player to reach the maximum height at the position of the basket

Attached to this thread is my solution, however the wording of the question is puzzling me and I do not know if the 1m that is mentioned is a point during his jump or the maximum height of his jump. My solution is based off of assuming that the 1m mentioned is the maximum height.

Basically I am asking if my solution is right or wrong and if anyone can point me into the right direction,

Thanks


Homework Equations



All relevant equations are listed in the attached files

The Attempt at a Solution



See the attached files below:

question a.jpg


question b.JPG


Thanks for the help
 
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I agree with your first answer, except I got 4.43 instead of 4.42, using g = 9.81. I did not do the angle calculation - just completed your initial calculation for v.

For the second part, I interpreted the question to mean the horizontal distance only and used d = vt = 6*0.45 = 2.71 m.
 

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