What was the average force applied to the box in the direction of motion?

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SUMMARY

The average force applied to a 7 kg box, which accelerates from 2 m/s to 4 m/s over a horizontal distance of 5 meters with a coefficient of kinetic friction of 0.1, is calculated to be approximately 10.2 N. This calculation involves determining the net force required for acceleration and accounting for the frictional force opposing the motion. The frictional force is calculated using the formula F_friction = μ * m * g, where μ is the coefficient of kinetic friction, m is the mass, and g is the acceleration due to gravity.

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A 7 kg box increases its speed form 2 to 4 m/s over a horizontal distance of 5 meters. coefficient fo kinetic friction is .1. what was the average force applied tothe box int he direction of the motion?
 
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Could you show some of your working or ideas?
 

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