What Was the Average Velocity of the Hiker During the Trip?

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Homework Help Overview

The discussion revolves around calculating the average velocity of a hiker who walks a certain distance in different directions over a specified time. The problem involves understanding the concepts of velocity as a vector quantity and the distinction between average speed and average velocity.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the definition of velocity and its vector nature, questioning the method of averaging speeds versus calculating total distance over total time. There is discussion about the need to account for direction when calculating average velocity.

Discussion Status

Participants are engaged in clarifying the correct approach to finding average velocity. Some have suggested using total distance and total time, while others are checking assumptions about the direction of the hiker's movement. Guidance has been offered regarding the importance of parentheses in calculations.

Contextual Notes

There is an ongoing exploration of the correct mathematical setup for the problem, with emphasis on the need to consider the return trip as a negative displacement. Participants are navigating through the implications of vector quantities in their calculations.

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Homework Statement



a hiker walks 6.7 miles to the east in 5.1 hours. then turns around and walks 1.1 miles to the west in 1 hour. what was her average velocity during the trip?
A 1.2mph
B 1.3mph
C .92mph
D 3.9mph

Homework Equations


not sure how to write what i used


The Attempt at a Solution


6.7/5.1=1.3
1.1/1=1.1
1.3+1.1=2.4/2=1.2
 
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It seems you're not done yet! :smile:

Let's start with the word "velocity".
Do you know what it means?
That is, is it a scalar or a vector?

Second, the term "average velocity".
What you should know is that you shouldn't average the speeds of the first part and the second part.
Instead you should calculate the total distance and divide that by the total time.
 
velocity is a vector because it has a magnitude and a direction.
so i should do something like 6.7+1.1/5.1+1=7.8/6.1=1.27
 
You just got the "average speed".
To get the "average velocity" you need to take into account that the second part of the trip is back.

(And please add parentheses when they are required. :wink:)
 
okay so how do i do that??
 
Going back is "minus" vector wise.
 
so should i do 6.7-1.1/5.1+1
 
Shall we make that: (6.7-1.1)/(5.1+1)?
The parentheses are really required.
Otherwise you're quite right.
 
okay. i got why the () are required. haha thanks i think I am almost done
 
  • #10
Yeah, I think so too...
 

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