What was the energy level of the individual electron of hydrogen atom ( Η )?

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SUMMARY

The energy level of an individual electron in a hydrogen atom can be determined using the wavelength of emitted radiation. In this case, a wavelength of 121 nm corresponds to the transition of the electron from a higher energy level to the ground state. The relationship between photon wavelength and energy is defined by the equation E = hc/λ, where E is energy, h is Planck's constant, c is the speed of light, and λ is the wavelength. Thus, the energy level of the excited electron can be calculated directly from the given wavelength.

PREREQUISITES
  • Understanding of the Bohr model of the hydrogen atom
  • Familiarity with the equation E = hc/λ
  • Basic knowledge of electromagnetic radiation
  • Concept of energy levels in quantum mechanics
NEXT STEPS
  • Learn about the Bohr model of the hydrogen atom
  • Study the derivation and application of the equation E = hc/λ
  • Explore the concept of energy transitions in quantum mechanics
  • Investigate the significance of spectral lines in atomic physics
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Chemistry students, physics enthusiasts, and educators seeking to understand atomic energy levels and photon interactions.

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Homework Statement


When a excited atom hydrogen ( wavelength ) de-energized emits energy and the electron returns to the fundamental situation. If the wavelength of the radiation emitted is 121 nm, to find what was the energy level of the individual electron of hydrogen atom ( Η ) in the excited state of it.



Homework Equations


I don't know how to solve this so please help me


The Attempt at a Solution


Please help me understand better this chemistry problem and his solution if you want be analytic to the solution
Thanks to all will help me I will be gratefully
 
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