What Was the Splashdown Speed?

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SUMMARY

The discussion centers on calculating the splashdown speed of a 60 kg stuntperson who jumps off a cliff at 4.6 m/s and lands in a river 10.2 m below. The key equations used are the conservation of mechanical energy, specifically TMEi = TMEf, where potential energy (PE) and kinetic energy (KE) are considered. The participant initially set up the equation correctly but struggled with the calculations, particularly regarding significant figures, which are crucial for obtaining the correct answer in WebAssign. The final splashdown speed can be accurately determined by ensuring proper calculation and significant figure adherence.

PREREQUISITES
  • Understanding of potential energy (PE = mgh)
  • Familiarity with kinetic energy (KE = (1/2)mv^2)
  • Knowledge of the conservation of mechanical energy principle
  • Basic skills in solving algebraic equations
NEXT STEPS
  • Review the principles of conservation of energy in physics
  • Learn about significant figures and their importance in scientific calculations
  • Explore projectile motion equations for further understanding of motion dynamics
  • Practice similar problems involving energy conservation and motion to solidify concepts
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Students studying physics, particularly those focusing on mechanics and energy conservation, as well as anyone preparing for physics homework or exams involving similar calculations.

innersmile
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1. A 60 kg stuntperson runs off a cliff at 4.6 m/s and lands safely in the river 10.2 m below. What was the splashdown speed?



Homework Equations


PE = mgh
KE = (1/2)mv^2
PEi +KEi = PEf + KEf
(TMEi) = (TMEf)

The Attempt at a Solution



I really had no idea how to start this but this is what i did:
i used TMEi = TMEf where the mass would cancel out
so the equation you end up with would be
(60 kg)(9.8 m/s2)(10.2) + (1/2)(60 kg)(4.6 m/s)^2 = (1/2)(60kg)(v^2) << i don't think you have to add PEf to that because the height is zero

but i didn't get the right answer. I'm doing this for a webassign..

thanks for the help
 
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You could try solving it using projectile motion equations, to see what answer you get.
What number did you get out of that calculation, by the way? Maybe you made an error?
 
innersmile said:
1. A 60 kg stuntperson runs off a cliff at 4.6 m/s and lands safely in the river 10.2 m below. What was the splashdown speed?



Homework Equations


PE = mgh
KE = (1/2)mv^2
PEi +KEi = PEf + KEf
(TMEi) = (TMEf)

The Attempt at a Solution



I really had no idea how to start this but this is what i did:
i used TMEi = TMEf where the mass would cancel out
so the equation you end up with would be
(60 kg)(9.8 m/s2)(10.2) + (1/2)(60 kg)(4.6 m/s)^2 = (1/2)(60kg)(v^2) << i don't think you have to add PEf to that because the height is zero

but i didn't get the right answer. I'm doing this for a webassign..

thanks for the help

You seem to have done it right. what did you get? How many sig figs did you use for your answer? webassign is picky about sig figs, you may have got the right answer but entered too many or too few sig figs (I am guessing too many)
 
thanks for the help!
yeah i set it up right but i must have done the calculations wrong...
thanks though!
 

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