What Was the Splashdown Speed?

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Homework Help Overview

The problem involves a 60 kg stuntperson running off a cliff at 4.6 m/s and landing in a river 10.2 m below. The objective is to determine the splashdown speed using principles of energy conservation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using the total mechanical energy equation (TME) to relate potential and kinetic energy. There is mention of using projectile motion equations as an alternative approach. Questions arise regarding the accuracy of calculations and the significance of significant figures in the context of the webassign.

Discussion Status

Some participants have provided guidance on checking calculations and considering significant figures. There is an acknowledgment that the setup of the problem appears correct, but discrepancies in the final answer have led to further questioning and exploration of potential errors.

Contextual Notes

Participants note that the problem is being solved for a webassign, which may impose specific rules regarding significant figures that could affect the final answer.

innersmile
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1. A 60 kg stuntperson runs off a cliff at 4.6 m/s and lands safely in the river 10.2 m below. What was the splashdown speed?



Homework Equations


PE = mgh
KE = (1/2)mv^2
PEi +KEi = PEf + KEf
(TMEi) = (TMEf)

The Attempt at a Solution



I really had no idea how to start this but this is what i did:
i used TMEi = TMEf where the mass would cancel out
so the equation you end up with would be
(60 kg)(9.8 m/s2)(10.2) + (1/2)(60 kg)(4.6 m/s)^2 = (1/2)(60kg)(v^2) << i don't think you have to add PEf to that because the height is zero

but i didn't get the right answer. I'm doing this for a webassign..

thanks for the help
 
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You could try solving it using projectile motion equations, to see what answer you get.
What number did you get out of that calculation, by the way? Maybe you made an error?
 
innersmile said:
1. A 60 kg stuntperson runs off a cliff at 4.6 m/s and lands safely in the river 10.2 m below. What was the splashdown speed?



Homework Equations


PE = mgh
KE = (1/2)mv^2
PEi +KEi = PEf + KEf
(TMEi) = (TMEf)

The Attempt at a Solution



I really had no idea how to start this but this is what i did:
i used TMEi = TMEf where the mass would cancel out
so the equation you end up with would be
(60 kg)(9.8 m/s2)(10.2) + (1/2)(60 kg)(4.6 m/s)^2 = (1/2)(60kg)(v^2) << i don't think you have to add PEf to that because the height is zero

but i didn't get the right answer. I'm doing this for a webassign..

thanks for the help

You seem to have done it right. what did you get? How many sig figs did you use for your answer? webassign is picky about sig figs, you may have got the right answer but entered too many or too few sig figs (I am guessing too many)
 
thanks for the help!
yeah i set it up right but i must have done the calculations wrong...
thanks though!
 

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