I What were the real results of the photoelectric effect experiment?

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The discussion highlights a discrepancy between Pearson Physics 12 and the PhET simulation regarding the photoelectric effect, specifically the relationship between light intensity, frequency, and photocurrent. While Pearson states that maximum current is the same for light of different frequencies but equal intensity, the PhET simulation shows that photocurrent increases with both intensity and frequency. Additionally, there is confusion in physics literature about the binding energy referenced in the photoelectric effect, particularly regarding Millikan's experiment, where the work function is often misidentified. The complexity of the work function is also noted, as it can relate to the image charge potential of emitted electrons. Overall, the conversation emphasizes the need for clarity and accuracy in understanding the photoelectric effect and its underlying principles.
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I am confused about information regarding the effect of light frequency on photocurrent in the Lenard's apparatus.
Pearson Physics 12 states:
"When the light sources have the same intensity but different frequencies, they produce the same maximum current"

However, Phet Simulation Photoelectric Effect seems to show that photocurrent changes with light frequency (eg see below for different photocurrents at 179 nm and 414 nm incident light wavelengths on sodium:

1654308153203.png

1654308178294.png
 
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jedishrfu said:
Khan Academy has a good description of the experiment and results found

https://www.khanacademy.org/science/physics/quantum-physics/photons/a/photoelectric-effect
Hmmm. That page doesn't appear to be in line with the PhET simulation, as it says that the electric current is proportional to the intensity of the light, not the frequency, whereas the PhET simulation has current increase as both intensity and frequency increase.
 
Ironically in almost all treatments in physics books (even at the university level) in
$$\hbar \omega=E_{\text{kin}}+W_B$$
for the famous experiment by Millikan with the stopping voltage the constant ##W_B## is quoted wrongly as the binding energy of the electrons in the cathode, rather it's the binding energy of the anode [1]. To establish this, by the way, took Millikan years, while the measurement of Plancks constant ##h=2 \pi \hbar## was pretty right from the very beginning.

[1] J. Rudnick, D. Tannhauser, Concerning a widespread error in the description of the photoelectric
effect, Am. J. Phys. 44, 796 (1976).
https://doi.org/10.1119/1.10130
 
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vanhees71 said:
Ironically in almost all treatments in physics books (even at the university level) in
$$\hbar \omega=E_{\text{kin}}+W_B$$
for the famous experiment by Millikan with the stopping voltage the constant ##W_B## is quoted wrongly as the binding energy of the electrons in the cathode, rather it's the binding energy of the anode [1]. To establish this, by the way, took Millikan years, while the measurement of Plancks constant ##h=2 \pi \hbar## was pretty right from the very beginning.

[1] J. Rudnick, D. Tannhauser, Concerning a widespread error in the description of the photoelectric
effect, Am. J. Phys. 44, 796 (1976).
https://doi.org/10.1119/1.10130

Actually, even that is not as clear-cut.

The nature of what a "work function" is is more complicated than such a simple answer. For example, in many instances, it is treated as simply the image charge potential of an electron emitted very near the surface of the material, thus creating an image charge of itself. The work function then is the minimum energy for this electron to overcome the image potential of itself.

See, for example, Pg. 10 of this article, which is a common usage of work function in accelerator physics and photoinjectors:

https://indico.cern.ch/event/218284...ts/352241/490774/Part_1_-Electron_sources.pdf

It is why one can modify the work function via Schottky effect, resulting in a lower work function and thus, higher electron emission and higher QE.

Zz.
 
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For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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