What will be the order of increasing radius?

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Discussion Overview

The discussion revolves around determining the order of increasing radius for the ions Ar, K+, and Ca2+. Participants explore concepts related to effective nuclear charge, nuclear charge, and the nature of the species being compared.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant suggests that the order of increasing radius is influenced by effective nuclear charge, proposing that Ar+2+ based on this concept.
  • Another participant argues that effective nuclear charge is unnecessary for this comparison and recommends using actual nuclear charge (atomic number) instead, implying that a higher nuclear charge results in a tighter binding of electrons.
  • A later reply reiterates the point about using actual nuclear charge and suggests a different order, proposing C as the answer.
  • One participant confirms the correctness of the last response without elaboration.

Areas of Agreement / Disagreement

Participants express differing views on the relevance of effective nuclear charge versus actual nuclear charge, indicating that there is no consensus on the best approach to determine the order of increasing radius.

Contextual Notes

Participants discuss whether to consider the noble gas and the metal ions as single atomic species or diatomic, raising questions about the appropriate radii to compare (metallic radius, Van der Waals radius, or ionic radius).

prakhargupta3301
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My answer is A.
Because effective nuclear charge would increase in order Ar<K+<Ca2+ and radius would be inverse of that.
However, the answer isn't that. Can you just point me?
Also, can you tell me in this question, do we think of the noble gas and the Ca and K ions as single atomic species or diatomic? Because Ar doesn't exist in single form right? So will be compare metallic radius(for metal ions) and Vander Waal's radius(for noble gas) or ionic radius for all three?
 

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You don't need any concept of effective nuclear charge here. Just use the actual nuclear charge (the atomic number). The higher the nuclear charge, the more tightly it will bind to electrons.
 
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Khashishi said:
You don't need any concept of effective nuclear charge here. Just use the actual nuclear charge (the atomic number). The higher the nuclear charge, the more tightly it will bind to electrons.
So I think C?
Am I correct please tell me.
 
yes
 

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