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Homework Statement
:[/B]
Homework Equations
: F = ma[/B]The Attempt at a Solution
:[/B]
The sum of the vertical forces for the second block is (mg)  T (tension). The tension of the second block is the parallel component of the first block which is (mgsin40). Therefore, the sum of the forces is (m2g  m1gsin40) = m(net)a. With numbers inserted, it's the following: [ (4 kg * 9.8 m/s^2)  (2 kg * 9.8 m/s^2 * sin40) = (4 kg + 2 kg) * a ] = a = 4.43 m/s^2. The answer in the back of the book is 0.933 m/s^2. What was my mistake?
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