What's the advantage of using a voltage buffer amplifier?

AI Thread Summary
A voltage buffer amplifier, or voltage follower, is primarily used to isolate circuits and prevent one from affecting another, particularly in scenarios involving high impedance sources like crystal oscillators. It provides unity gain while allowing for impedance transformation, which is crucial for maximizing power transfer to loads with varying resistances. By inserting a buffer between a signal source and a load, it maintains the stability of the source's output, preventing frequency and power fluctuations. This isolation ensures that the output circuit does not load down the input circuit, preserving signal integrity. Overall, using a voltage buffer enhances performance in electronic applications.
RonzRknob
Messages
4
Reaction score
3
i want to understand what's the advantage of using a voltage follower
 
Engineering news on Phys.org
A voltage follower is used to buffer the signal. It is helpful for changing impedance, too.

For example if you have a high impedance source that you cannot load, maybe a crystal oscillator, you can use the voltage follower to then distribute the signal to multiple loads, or maybe an amplifier that has a lower input impedance like a BJT.
 
  • Like
Likes Asymptotic, sophiecentaur and davenn
RonzRknob said:
i want to understand what's the advantage of using a voltage follower

Voltux said:
A voltage follower is used to buffer the signal. It is helpful for changing impedance, too.

For example if you have a high impedance source that you cannot load, maybe a crystal oscillator, you can use the voltage follower to then distribute the signal to multiple loads, or maybe an amplifier that has a lower input impedance like a BJT.
great answer, Voltux :smile:

@RonzRknob, a buffer, usually (but not always) has a gain of 1 ( unity gain) and is a great way to stop one circuit from affecting another

Using an op-amp in this configuration is a very popular practice eg …..
buffer.gif
upload_2018-8-26_12-36-9.png
jackormanopampbuffer-gif.gif
upload_2018-8-26_12-39-31.png

The sole purpose of a buffer circuit is to isolate the input circuit from the output circuit


Dave
 

Attachments

  • upload_2018-8-26_12-36-9.png
    upload_2018-8-26_12-36-9.png
    19.5 KB · Views: 2,863
  • upload_2018-8-26_12-39-31.png
    upload_2018-8-26_12-39-31.png
    23.4 KB · Views: 4,728
  • buffer.gif
    buffer.gif
    1.7 KB · Views: 3,879
  • jackormanopampbuffer-gif.gif
    jackormanopampbuffer-gif.gif
    1.4 KB · Views: 2,792
  • Like
Likes dlgoff and Asymptotic
@davenn , can you further explain me why isolating the input circuit from the output circuit is beneficial?
 
Imagine a source which has a series resistance of Rs and a load with resistance Rl. Try calculating how the power dissipated in the load changes as Rl changes. If Rl = 0 then there would be no voltage across it so the Power I*V would be zero. If RL was infinite there would be no current so again the power dissipated in the load would be zero. It so happens that the power is a maximum when Rl = Rs.

But what if they are fixed and RL <> Rs?

Inserting a buffer amplifier between the two allows you to change the impedance driving the load and maximise power transfer. This is what others mean by changing the impedance.
 
  • Like
Likes RonzRknob
RonzRknob said:
@davenn , can you further explain me why isolating the input circuit from the output circuit is beneficial?

I did answer that in post #3 as did @Voltux in post #2

His example of an oscillator circuit being affected ( loaded down) by the circuit placed on the output of the oscillator is an idea solution.
The circuit following the oscillator may be an amplifier stage, but just directly connection that amplifier to the output of the oscillator without any buffering isolation can cause the oscillator or function incorrectly, commonly by causing it to change it output frequency and or power output.
By putting a unity gain buffer stage in there between the oscillator and the amplifier, stops the amplifier stage from affecting the oscillators output. Thus the oscillator remains stable and its output doesn't frequency/power wobble all over the place.
 
CWatters said:
Imagine a source which has a series resistance of Rs and a load with resistance Rl. Try calculating how the power dissipated in the load changes as Rl changes. If Rl = 0 then there would be no voltage across it so the Power I*V would be zero. If RL was infinite there would be no current so again the power dissipated in the load would be zero. It so happens that the power is a maximum when Rl = Rs.

But what if they are fixed and RL <> Rs?

Inserting a buffer amplifier between the two allows you to change the impedance driving the load and maximise power transfer. This is what others mean by changing the impedance.
Thank you , that was helpful
 
  • Like
Likes dlgoff
davenn said:
I did answer that in post #3 as did @Voltux in post #2

His example of an oscillator circuit being affected ( loaded down) by the circuit placed on the output of the oscillator is an idea solution.
The circuit following the oscillator may be an amplifier stage, but just directly connection that amplifier to the output of the oscillator without any buffering isolation can cause the oscillator or function incorrectly, commonly by causing it to change it output frequency and or power output.
By putting a unity gain buffer stage in there between the oscillator and the amplifier, stops the amplifier stage from affecting the oscillators output. Thus the oscillator remains stable and its output doesn't frequency/power wobble all over the place.
Thanks Dave , I can now see it through
 
  • Like
Likes dlgoff and davenn
Back
Top