What's the speed of ball when travelling over the fence?

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The discussion revolves around calculating the speed of a baseball as it travels over a 4-meter high fence after losing half its energy to air resistance. The initial kinetic energy (KE) of the ball is calculated using the formula Ek = 0.5*m*v^2, where the mass is 0.4 kg and the initial speed is 20 m/s. Participants emphasize the need to correctly identify which energy component should be halved, specifically pointing out errors in the initial equation setup. There is confusion over how to apply the energy loss due to air resistance in the calculations. The conversation highlights the importance of accurately representing the initial kinetic energy in the equation to find the correct speed of the ball over the fence.
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Homework Statement


Two girls are playing baseball in a park. The batter hits the 400-g ball with a speed of 20.0 m/s. It travels over the park's fence that is 4.00 m high. Assuming that the ball loses half of its energy to air resistance, at what speed does the ball travel over the fence?

Homework Equations


Ek = 0.5*m*v^2
Ep = m*p*h


The Attempt at a Solution


0.5*(0.4Kg)*(20 m/s)^2 = 0.5 [(0.4Kg)(9.81 m/s^2)((4m) + 0.5(0.4Kg) Vf^2]
My answer was wrong.
 
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Have another think about the first 0.5 on the right of the =.
 
Hoyin said:
0.5*(0.4Kg)*(20 m/s)^2 = 0.5 [(0.4Kg)(9.81 m/s^2)((4m) + 0.5(0.4Kg) Vf^2]
My answer was wrong.

You're line of thinking is correct. Just stress on which energy needs to be reduced by half.
 
I tried reduce the Kinetic energy by half, but the answer is incorrect. Thanks.
 
Hoyin said:
I tried reduce the Kinetic energy by half, but the answer is incorrect. Thanks.
That's not what you've done in your equation. Check again.
 
Hoyin said:
I tried reduce the Kinetic energy by half, but the answer is incorrect. Thanks.
Which term in your equation represents the initial KE? Where is that multiplied by one half?
 
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