What's the total angular momentum operator for a system of two particles?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 3K views
AxiomOfChoice
Messages
531
Reaction score
1
Suppose we're in two dimensions, and both particles have mass 1.

Particle 1's location is given by its polar coordinates [itex](r_1,\theta_1)[/itex]; likewise for Particle 2 [itex](r_2,\theta_2)[/itex].

Is it true that the total angular momentum [itex]\vec{L}[/itex] is just the sum of the individual angular momenta of the particles: [itex]\vec{L} = \vec{L}_1 + \vec{L}_2[/itex]? If that's the case, can you give me the total angular momentum operator [itex]\vec{L}[/itex] as a differential operator?
 
Physics news on Phys.org
yeah, just add it up: [tex]L_j^z = -i\hbar \left[y_j\partial/\partial{x_j} - {x_j}\partial/\partial{y_j}\right][/tex] where j is the particle index. Keep in mind L_2 does not act on the coordinates for the first particle.