- #1

davekardle

- 23

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**What's the volume of water required inside the lock if...**

The dimension of the lock is:40 long x 3.5 height x 6 width

allowing 0.5 height.

The ship weights 400T plus 300T(LOAD)

total= 700T

whats the amount of water used per lock allowing allowing 0.5 m from the height?

What if the ship empties its load on the lock ? the density of the load is 755kg/m^3.

2. Homework Equations

Archimedes principle

Mass of water displaced

3. The Attempt at a Solution

Mass of water displaced by the boat mass = 700T

VOLUME = 700M^3

Total volume inside the lock allowing 0.5

(3x40x6)m^3 - 700M^3

Is that correct ?

How about if the ship empties its load on the lock ?