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What's the volume of water required inside the lock if

  • Thread starter davekardle
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  • #1
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What's the volume of water required inside the lock if....

Homework Statement



The dimension of the lock is:40 long x 3.5 height x 6 width
allowing 0.5 height.

The ship weights 400T plus 300T(LOAD)
total= 700T

whats the amount of water used per lock allowing allowing 0.5 m from the height?

What if the ship empties its load on the lock ? the density of the load is 755kg/m^3.

Homework Equations



Archimedes principle
Mass of water displaced

The Attempt at a Solution



Mass of water displaced by the boat mass = 700T
VOLUME = 700M^3
Total volume inside the lock allowing 0.5

(3x40x6)m^3 - 700M^3

Is that correct ?

How about if the ship empties its load on the lock ?
 

Answers and Replies

  • #2
rude man
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Homework Statement



The Attempt at a Solution



Mass of water displaced by the boat mass = 700T
VOLUME = 700M^3
Total volume inside the lock allowing 0.5

(3x40x6)m^3 - 700M^3

Is that correct ?
Yes.

How about if the ship empties its load on the lock ?
The new displaced volume of water will be how much? So the level of the lock rises by how much?
 
  • #3
SteamKing
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Duplicate posting in several other forums.
 

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