What's wrong with my calculation?

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The discussion centers on the misconception of calculating kinetic energy for a particle with mass traveling at the speed of light. The initial calculation incorrectly applies classical physics formulas, leading to a misunderstanding of mass increase at relativistic speeds. It emphasizes that the correct approach involves using relativistic formulas, which account for the effects of traveling near light speed. The distinction between rest mass and relativistic mass is crucial, as mass is typically interpreted as rest mass in these contexts. Ultimately, the error lies in applying classical equations to scenarios governed by relativity.
scilover89
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"If a particle which has mass travel at the speed of light, the particle mass will reach infinity, which require infinity energy to move it, thus particle can't travel beyond the speed of light."
I made an calculation about it.(And it turned out to be wrong) However, I couldn't find the mistake!
This is my calculation:
Let the mass = 1kg, and the velotion = c
Kinetic energy gained while travelling=0.5mc^2
=0.5c^2
When these energy is fully converted into mass,
Einstein's Equation:E=mc^2
0.5c^2=mc^2
m=0.5
The mass gained by the particle is 0.5, not infinity? Why?
 
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That equation describes the amount of energy released when turning mass into energy - it has nothing to do with relativistic mass.
 
and besides m = 1kg is nonsense because you are confusing rest-mass and relativistic mass. Keep in mind that mass is always interpreted as rest-mass though the epitheton rest is left behind...

marlon
 
I do not have a good working knowledge of physics yet. I tried to piece this together but after researching this, I couldn’t figure out the correct laws of physics to combine to develop a formula to answer this question. Ex. 1 - A moving object impacts a static object at a constant velocity. Ex. 2 - A moving object impacts a static object at the same velocity but is accelerating at the moment of impact. Assuming the mass of the objects is the same and the velocity at the moment of impact...

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