Einstein's E=mc^2 equation -- question....

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  • Thread starter Felix Quintana
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    E=mc^2
  • #1
Let's say we have a particle traveling at the speed of light, energy would be E=mc^2, momentum would be then p=mc, let's manipulate, m=E/c^2, momentum would then be p=E/c, but what energy does that equal, the particle only has kinetic energy correct? Then it would be p=1/2mc. Where is the other half?! In spring or gravitational?
 

Answers and Replies

  • #2
Partices with mass don't travel with speed of light.
 
  • #3
Oh yeaaaah I was told that before, I forgot, but can we say what if theoretically ?
 
  • #4
No we can't.
 
  • #5
Oh yeaaaah I was told that before, I forgot, but can we say what if theoretically ?
No, That's asking "What would the rules be if I were allowed to break the rules?"
 
  • #6
Interesting. Thank you very much sir... This, and all my abundant amount of strands.
 
  • #7
No, That's asking "What would the rules be if I were allowed to break the rules?"
Finally someone who speaks my language.
 
  • #8
I think, excuse me though, for I am a amateur, wild idea, but what if space creates the other half through spring, as if space is a flat plane but spring like, and it created the energy, I also think of the same thing with gravity and so one... I sometimes create hypothesizes and later find out I am correct, but not always...Think crazy outside the box ideas.:wink:
 
  • #9
Keep that spirit, but pay some attention to what others have thought out over the ages too !
 
  • #10
I'm usually beat to the punch! Especially members of the golden age and on.
 
  • #11
Know the feeling :wink: , been there too !
 
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  • #12
Let's say we have a particle traveling at the speed of light, energy would be E=mc^2
E=mc^2 is the formula for an object at rest (p=0). The full formula (in units where c=1) is E^2-p^2=m^2. So if p=E then m=0.
 
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