Gordon Watson
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Excuse delayed reply here. I answered a related post earlier, but wanted to be sure that the issues here were clearly covered.vanesch said:Here, things bug. Maybe this comes about because of a misunderstanding of the exact set-up, or about what exactly we are talking about, I don't know. There's no "double-valuedness" of any angle.
Consider the set-up as follows:
On Monday, Alice puts her analyser vertically and her detector clicks when she gets an "up" result. Bob puts his analyser at 45 degrees with the vertical (s times angle is then 22.5 degrees, right) towards the window of the room, and his detector clicks also when he gets an "up" result. An electronic circuit links Alice's and Bob's detector signals to a counter, which counts each time there is a simultaneous click on both detectors.
Carol starts the electron-pair source in the middle, and let's it generate 1 million electron-pairs during the afternoon.
Quantum mechanics predicts that at the end of the afternoon, the counter will read something like 73 000 counts.
On Tuesday, Alice leaves her installation in place, but Bob rotates his axis until it is horizontal (so s times angle is 45 degrees), with his "up" direction pointing towards the window.
When Carol starts the 1 million electron pair source again, quantum theory predicts that the counter will read 250 000 at the end of the afternoon.
On Wednesday, Alice, Bob and Carol go to a party.
On Thursday, Bob leaves his installation in the horizontal direction, but now Alice rotates her axis also in the direction of the window, over 45 degrees. Carol makes the source again run and produce 1 million electron pairs. Quantum mechanics predicts that the counter will read 73 000 counts.
The whole point is that the statistical mixture of the 1 million electron pairs is each time the same ; that the source didn't suffer any influence from the choice of settings.
So if on Friday, Alice and Bob randomly change their axes and we take data until we have 1 million events where Alice and Bob had aligned their axes as on Monday (so only considering those results when by coincidence Alice and Bob had their axes as on Monday), we expect to find statistically the same result as on Monday ; if we take data until we have 1 million events where Alice and Bob had aligned their axes as on Tuesday (so considering only those results where by coincidence Alice and Bob had their axes as on Tuesday), we expect to find the same result statistically as on Tuesday. And same for Thursday. Also, if by coincidence Alice and Bob put their axes parallel, we find that the counter reads 0.
The results will be the same if the source is generating statistically identical sets of events, independently of how the axes are set.Now, if we are to explain the results of Alice and Bob in a LR way, we have to assume that each pair sent out by the source must fall in 1 of 8 categories.
In the first category are the pairs which would give us a click in Alice's counter when it is vertical, and no click in Bob's counter when it is vertical ; that it would give us a click in Alice's counter when it was at 45 degrees, and no click in Bob's counter when it was at 45 degrees, and again that it would give a click in Alice's counter when at 90 degrees, and no click in Bob's counter when it was at 45 degrees. We write it as (+ + +). So events in this category will always give a click in Alice's counter and never one in Bob's counter.
and so on for the 7 other categories.
Note that there are no other possibilities: the 8 categories cover entirely the possibilities of the electron pair behaviour. It is for instance not possible that a pair wouldn't give a click in any Alice counter nor in any Bob counter. If a pair doesn't give a click in a vertical Alice counter, then it MUST give a click in a vertical Bob counter. So if we know the behaviour of a pair at Alice, we know that the behaviour at Bob's is complementary.
So the 1 million events must be subdivided in these 8 categories, with:
P1 * 1000000 = N1 the number of pairs in the first class,
P2 * 1000000 = N2 the number of pairs in the second class
etc...
Well, the number of pairs that belong to those that were counted on Monday are those in class 2 AND those in class 4. Each of the pairs in one of these classes will make the counter count, so we have that:
N2 + N4 = 73 000 up to statistical errors.
The counts on Tuesday are N3 + N4 = 250 000 up to statistical errors
The counts on Thursday are N3 + N7 = 73 000 up to statistical errors.
Well, you can't find such (positive) numbers N2, N3, N4, and N7.
Simply because if you add the counts on Monday and those on Thursday,
N2 + N3 + N4 + N7 = 146 000
and the counts on Tuesday are only N3 + N4 and they are LARGER: 250 000.
There's no "double angledness" or whatever here. There are specific measurements, with specific outcomes, and you CAN'T explain them with a pre-determined mixture of events. That's the point.
I didn't understand the reference to windows, and some settings pointing to them. For example, this confused me: "with his "up" direction pointing towards the window."
However, I believe that the outcomes relate to QM outcomes, as given in that other reply. So, per Table 2 in PDF2, we are not disagreeing about valid QM results.
However: With the numbers that were meant to be "pedagogical" -- they are numbers derived from L*R. Such numbers do not deliver the QM numbers directly. Instead they deliver the numbers that correctly relate to the "L*R 3-orientations, 2-angles, 1 bi-angle" thought-experiments that characterize L*R.
To get the QM numbers that you seek to check, the "L*R 3-orientations, 2-angles, 1 bi-angle" results must be reduced to a result that QM relates to. QM results involve and relate to "2-orientations, 1-angle" tests.
These reductions are fully detailed in Appendix A of PDF2. They yield (as shown in Table 2 of PDF2), correctly, every possible QM number that relates to the experiment.
On this basis, I'd be pleased if you would reconsider the "pedagogical" merits of my P1-P8 L*R-based numbers.
Many thanks.
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