In the canonical quantum gravity, Hamiltonian equal zero, why? Since the split is space, the time is a constant? or the space-time is Ricci-flat?(adsbygoogle = window.adsbygoogle || []).push({});

In other words, if the space-time is Ricci-flat whether time supersurface, Hamiltonian equal zero?

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# Wheeler-Dewitt equation and canonical quantum gravity

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