Interesting, I guess I've to read the bruchure again.
But why then do they write
$$N_A=6.xxx \cdot 10^{23} \frac{1}{\text{mol}}$$
oif ##\text{mol}## had the dimension of ##N## (which dimension is in fact 1). That's very confusing. Maybe I get something wrong here.
But let's take the "natural units" used in HEP physics. There you have ##\hbar=c=k_{\text{B}}=1##. Then everything is measured in principle using only one unit, e.g., GeV. In addition for some quantities one uses fm. The conversion is simply ##1 fm \simeq \frac{0.197}{\mathrm{GeV}}##.
Maybe I'm using the expression "dimension" wrong, but which dimension a quantity takes, depends on the system of units used, i.e., in the HEP natural units masses, energies, momenta, and temperatures have the same dimension. The same holds for lengths and times. Velocities are dimensionless.
Another example is electromagnetism, where the quantities have different dimensions depending on whether you use Gaussian/Heaviside Lorentz or SI units. In Gaussian or Heaviside units the components ##\vec{E}## and ##\vec{B}## of the electromagnetic field-strength tensor take the same dimension, while they are different in the SI. The reason is that in the SI an additional unit for electric charge, C (or equivalently electric current, the Ampere) is introduced, which enforces the introduction of one more conversion factor, ##\mu_0## in addition to ##c##, which is used in Gaussian and Heaviside units es well.
In Planck units all quantities would have the same dimension, namely 1, i.e., all quantities are dimensionless.
Of course, you can also specify "dimensions" independent from units. Is it this sense the SI brochure uses the word "dimension"? Than it's clear that I used the wrong meaning in context of the SI.