When is a function non-differentiable?

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Discussion Overview

The discussion revolves around the concept of differentiability of functions, exploring when a function may be non-differentiable. Participants consider examples of functions, such as the absolute value function and the Weierstrass function, and discuss definitions related to differentiability.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant notes that the function f(x) = x is differentiable, but raises the question of when a function becomes non-differentiable, mentioning cusps as a potential case.
  • Another participant cites the Weierstrass function as a well-known example of a function that is nowhere differentiable.
  • A different participant introduces a definition of differentiability based on limits from both sides, referencing the delta-epsilon model and suggesting the need to consider general norms.
  • One participant expresses intent to apply the definitions provided in the discussion.

Areas of Agreement / Disagreement

Participants present multiple viewpoints on differentiability, with some examples agreed upon, but no consensus on a comprehensive list of cases or definitions exists.

Contextual Notes

The discussion includes references to specific mathematical definitions and concepts, but lacks clarity on how these definitions apply universally across different types of functions.

Who May Find This Useful

Readers interested in mathematical analysis, particularly those exploring the properties of differentiable functions and examples of non-differentiable functions.

damabo
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I know that e^{rx} is an infinitely differentiable function.
However, say you have f= x. this is clearly one time differentiable, giving 1. a second time it can be derived as well, giving 0. is 0 differentiable, indeed differentiation gives zero.
So when is a function non-differentiable. I'm thinking of cusps, such as on x=0 with the function f=|x|, or other functions where the derivative is undefined. correct? are there other cases? it would also be interesting to see a function that is only finitely differentiable.
 
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that's a nice one!
 
thanks, will apply that formula.
 

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