- #1

andresB

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Acording to the non-Abelian stokes thoerem

http://arxiv.org/abs/math-ph/0012035

I can transform a path ordered exponential to a surface ordered one.

P e

where

P e

where the RHS is just a ordinary surface exponential.So the questions are

1)is my suposition right?

2) if afirmative how cah i prove that fact?

3) if negative, why? and what properties should have the conection A and/or the curvature F to ensure (*)

http://arxiv.org/abs/math-ph/0012035

I can transform a path ordered exponential to a surface ordered one.

P e

^{[itex]\oint[/itex][itex]\tilde{A}[/itex]}=*P*e^{∫F}where

*F*is some twisted curvature;*F*=U^{-1}FU, and U is a path dependet operator.So, I have a system where every element of the curvature 2-form F commute with each other, i just have the feeling that it is true thatP e

^{[itex]\oint[/itex][itex]\tilde{A}[/itex]}=e^{∫F }(*)where the RHS is just a ordinary surface exponential.So the questions are

1)is my suposition right?

2) if afirmative how cah i prove that fact?

3) if negative, why? and what properties should have the conection A and/or the curvature F to ensure (*)

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