When is the equation FD = 1/4 AV^2 false and what is the error in the equation?

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SUMMARY

The discussion centers on the drag force equations, specifically comparing FD = 1/2 CD * ApV^2 with the approximate formula FD = 1/4 AV^2. The latter is valid under certain conditions, particularly for speeds below the speed of sound in normal air. The primary error in using the 1/4 AV^2 equation lies in its simplification, which neglects the drag coefficient (CD) and assumes a constant relationship that does not hold in all scenarios. Understanding the proportionality of drag force to area, density, and velocity is crucial for accurate calculations.

PREREQUISITES
  • Understanding of fluid dynamics principles
  • Familiarity with drag force concepts
  • Knowledge of the drag coefficient (CD)
  • Basic physics of motion and forces
NEXT STEPS
  • Study the derivation of the drag force equation FD = 1/2 CD * ApV^2
  • Learn about the significance of the drag coefficient (CD) in fluid dynamics
  • Explore the effects of varying cross-sectional area on drag force
  • Investigate the behavior of drag force at different velocities, particularly near the speed of sound
USEFUL FOR

This discussion is beneficial for physics students, engineers, and anyone involved in aerodynamics or fluid mechanics, particularly those looking to deepen their understanding of drag force calculations.

jason bourne
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Homework Statement



I know that standard formula is, FD = 1/2 CD *ApV^2


FD = Drag Force. SI: N
CD = Drag Coefficient. SI: Dimensionless (Typical Values)
A = Coss-sectional Area perpendicular to the flow. SI: m2
r = Density of the medium. SI: kg/m3
v = Velocity of the body relative to the medium. SI: m/s

But our prof also said there's another formula for drag force,

FD = 1/4 AV^2

(Its is not supposed to be equal but approximately)

So the question is when is the equation above false, what's the error in the equation that makes it approximate.


Homework Equations



FD = 1/4 AV^2

FD = 1/2 CD *ApV^2



The Attempt at a Solution



I searched everywhere on wikipedia and NASA site and no luck and I don't know integration yet so can't follow the complicated math. Please anyone can help me.
 
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Look closely at the second equation. It is a private case of the first.

The factor of \tfrac{1}{2} is pretty weird too.

All you need to remember is what the drag force is proportional to, and that's fairly simple:
The higher the area perpendicular to the flow - the greater the drag.
The greater the density of the medium - the greater the drag.
The greater the square of the velocity of the object wrt the medium - the greater the drag
And then there's just some constant.
 
Thanks for your reply. But it was like a bonus question kind of thing, why 1/4 AV^2 instead of the other equation, he said the 1/4 will work for any speed less than speed of sound and uses normal air and something. And he said 1/4 is not the error that # is precise, so the problems got to be in the AV^2.hmm.
 

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