When should the nuclear spin be included in atomic spectroscopic notation?

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SUMMARY

The inclusion of nuclear spin in atomic spectroscopic notation is definitively not part of the term symbol itself, as established in the Russell-Saunders coupling scheme. In this context, the total spin (S) pertains solely to the electron spin, while nuclear spin is represented in the quantum number F. For example, in the notation ${3}^P_{2}$, the total spin is one, and the total angular momentum J is calculated as J=S+L=2, without considering the spin of the odd nucleon.

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  • Understanding of Russell-Saunders coupling scheme
  • Familiarity with atomic energy state notation
  • Knowledge of quantum numbers (S, L, J, F)
  • Basic principles of nuclear spin and electron spin
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This discussion is beneficial for physicists, particularly those specializing in atomic and quantum physics, as well as students seeking to deepen their understanding of atomic spectroscopic notation and the role of nuclear spin.

passingthru
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Forgive me if this has already been discussed. I've been searching and haven't found it. When summing the spin of an atom in the Russell-Saunders coupling scheme, some texts include the spin of an odd nucleon, and some don't. For example, if an atomic energy state is described as ${3}^P_{2}$, this means that the total spin is one, and since $L=1$, $J=S+L=2$. If this is a hydrogen atom, apparently, the spin of the proton is included. Many discussions of this never even bring up the nucleus. When should the spin of an odd nucleon be included?
 
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passingthru said:
When should the spin of an odd nucleon be included?
Never. The spin ##S## is the total electron spin.

Nuclear spin only comes into the quantum number ##F##. It is never part of the term symbol itself (the hyperfine state is stated in addition the term symbol, e.g., 2S1/2 ##F=1##).
 

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