When Should You Use the Delta Symbol in Equations?

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SUMMARY

The discussion centers on the correct usage of the delta symbol in equations, specifically in thermodynamics and electric potential. It is established that the delta symbol indicates a change in a variable, such as in the equation ΔU = (3/2)nRΔT, which represents the change in internal energy based on temperature change. The necessity of the delta symbol is clarified; it cannot be arbitrarily added or removed without altering the meaning of the equation. The distinction between potential functions and potential energy functions is also emphasized, highlighting that while the absolute value of potential can vary, the difference remains consistent.

PREREQUISITES
  • Understanding of thermodynamic equations, specifically internal energy calculations.
  • Familiarity with electric potential and potential difference concepts.
  • Basic algebra skills for manipulating equations involving variables.
  • Knowledge of the relationship between temperature and internal energy in ideal gases.
NEXT STEPS
  • Study the derivation of the first law of thermodynamics and its implications for internal energy.
  • Learn about electric fields and their relationship to potential difference in circuits.
  • Explore the concept of potential energy in gravitational fields and its mathematical representation.
  • Investigate the significance of reference points in measuring potential energy and electric potential.
USEFUL FOR

Students and professionals in physics, particularly those studying thermodynamics and electromagnetism, as well as educators seeking to clarify the application of delta symbols in equations.

AznBoi
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Okay, so how do you know when to put a delta symbol in front of a variable? For example, U=\frac{3}{2}nRT however, it can also be written as \Delta U=\frac{3}{2}nR\Delta T --Change in Internal energy of a system

I'm pretty sure that this isn't the case for many equations such as: \Delta V=Ed--Potential difference, where there is no delta signs on the right hand side of the equation right?

Are these deltas just suppose to be memorized or is there a way to add or remove them from equations while still being able to achieve the correct answer?
 
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No, you can't remove or add deltas to an equation, unless you happen to get really lucky and what you were subtracting happened to be zero. For example

\Delta U=\frac{3}{2}nR\Delta T

We know U=\frac{3}{2}nRT

So if we have intitial internal energy U_i and final internal energy U_f then U_f-U_i is by definition the change in internal energy. But U_f=\frac{3}{2}nRT_f where T_f is the final temperature (assuming the quantity of material does not change, and of course R can never change) and U_i=\frac{3}{2}nRT_i where T_i is the initial temperature. So U_f-U_i=\frac{3}{2}nRT_f-\frac{3}{2}nRT_i=\frac{3}{2}nR(T_f-T_i)
So the fact that you added delta symbols isn't mysterious, it's just basic algebra
 
Office_Shredder said:
No, you can't remove or add deltas to an equation, unless you happen to get really lucky and what you were subtracting happened to be zero. For example

\Delta U=\frac{3}{2}nR\Delta T

We know U=\frac{3}{2}nRT

So if we have intitial internal energy U_i and final internal energy U_f then U_f-U_i is by definition the change in internal energy. But U_f=\frac{3}{2}nRT_f where T_f is the final temperature (assuming the quantity of material does not change, and of course R can never change) and U_i=\frac{3}{2}nRT_i where T_i is the initial temperature. So U_f-U_i=\frac{3}{2}nRT_f-\frac{3}{2}nRT_i=\frac{3}{2}nR(T_f-T_i)
So the fact that you added delta symbols isn't mysterious, it's just basic algebra


Ohhh lol. What about the potential difference equation? How come there is a delta in front of the (V)?
 
There's no need to memorize anything.

If the quantity on the left hand side has a sensible definition on its own (like U in terms of T), then the change in that quantity would have to be expressed in terms of the change in the variable it depends on (T in this case).

Potential functions and potential energy functions are different, in the sense that the potential at a single point has a completely arbitrary definition (i.e., the reference point with respect to which you measure the potential could change, adding or subtracting a constant value to all potentials at all points). This doesn't matter, because the *difference* in potential between two points will remain the same regardless. This is what is given by Ed and what is physically relevant.

A good analogy is elevation. Let's say you're on an inclined plane (to keep the math simple). Then let's call the slope, or gradient of the incline E (it plays an analogous role to the electric field in this analogy). Let's call the distance you have traveled up the plane d. Then the total gain in elevation is just the slope times the horizontal distance:

\Delta h = Ed

But what are you measuring the elevations with respect to (i.e. where do you define h = 0 to be)? It could be relative to sea level (as is the case in real life), or it could be relative to where you are standing now (in which case sea level would have a negative elevation). The point is, it really doesn't matter. It doesn't affect the change in elevation \Delta h [/tex] between two points on the incline separated by distance d. That will always be given by Ed. So if all you are concerned with is your gain in elevation with horizontal distance travelled, then this will be your formula of interest.
 
Last edited:
Voltage, like gravitational potential, is in reference to an arbitrary zero point. You can think of the change in voltage in a uniform electric field as the field times the change in distance. But were usually only concerned with the relative change in potential between 2 points
 
AznBoi said:
Ohhh lol. What about the potential *difference* equation? How come there is a delta in front of the (V)?


The answer to your question lies in the question itself. The potential difference is (not surprisingly) the difference in electric potential.
 

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