When two resistors are in parallel....(rational functions)

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SUMMARY

When two resistors, denoted as $$s$$ and $$t$$, are connected in parallel, their combined resistance $$R$$ is calculated using the formula $$\frac{1}{R} = \frac{1}{s} + \frac{1}{t}$$. To determine the change in resistance when $$s$$ is increased by 1 unit and $$t$$ is decreased by 1 unit, first compute the initial resistance $$R_i$$ and then the final resistance $$R_f$$. The change in resistance is given by the equation $$\Delta R = R_f - R_i$$, which provides a clear method for evaluating the impact of the changes in resistor values.

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When two resistors, $$s$$ and $$t$$, are connected in parallel, their combined resistance, $$R$$, is given by $$\frac{1}{R}$$ = $$\frac{1}{s}$$ + $$\frac{1}{t}$$

If $$s$$ is increased by 1 unit and $$t$$ is decreased by 1 unit, what is the change in $$R$$?(I'm not really sure how to do this...help would be appreciated! Thanks.)
 
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I would first solve for $R$ and call this $R_i$, or the initial resistance. The substitute $s+1$ for $s$ and $t-1$ for $t$ in that expression and call that $R_f$, or the final resistance. Then compute the change in the resistance by:

$$\Delta R=R_f-R_i$$
 

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