When Will the Thrown Mass Overtake the Dropped Shot Put in Freefall?

  • Thread starter Thread starter yakiland
  • Start date Start date
  • Tags Tags
    Freefall
Click For Summary
SUMMARY

The discussion centers on a physics problem involving two objects: a 1.5 kg shot put dropped from 60 meters and a 100 g mass thrown downward at 10 m/s from 70 meters. The key equations used include kinematic equations for freefall, specifically x = (v + u/2) * t and v² = u² + 2ax, with gravitational acceleration set at 9.8 m/s². The objective is to determine the time at which the thrown mass overtakes the dropped shot put by equating their respective positions over time.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of freefall dynamics and gravitational acceleration
  • Basic algebra for solving equations
  • Concept of relative motion in physics
NEXT STEPS
  • Study kinematic equations in detail, focusing on freefall scenarios
  • Explore the concept of relative motion and how it applies to falling objects
  • Practice solving similar physics problems involving multiple objects in freefall
  • Learn about the effects of air resistance on falling objects
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in solving real-world motion problems involving freefall dynamics.

yakiland
Messages
4
Reaction score
0
Heres a question I am really stuck on...

Homework Statement


If Person A drops a shot put weighing 1.5 kg from a height of 60m, and at exactly the same time Person B throws down a 100g mass at a speed of 10 m/s from 70m up, at what time would the mass overtake the shot put?


Homework Equations


mass is irrelevant due to freefall.

to find the total time it takes for each item to reach the ground, i used
x=(v+u/2)*t
AND
v^2=u^2+2ax

acceleration due to gravity=9.8m/s^2

The Attempt at a Solution


I have no idea where to start...
 
Physics news on Phys.org
If you write out the x equations for both the A ball and B ball, then you can equate the two and find the time they occupy the same position.
 

Similar threads

Replies
3
Views
10K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
23
Views
3K
  • · Replies 26 ·
Replies
26
Views
3K