Where Did I Go Wrong? Solving for Angular Momentum in Air Table Puck Collision

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Homework Help Overview

The discussion revolves around calculating angular momentum in the context of a collision involving air table pucks. Participants are examining the relationship between the center of mass (CoM) and the distances involved in the problem.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to clarify the calculation of the distance from the CoM to the center of one of the pucks, questioning the assumptions made about the CoM's position. There is a focus on deriving the distance in symbolic form and ensuring the correct notation is used.

Discussion Status

The discussion is active, with participants providing insights and clarifications regarding the calculations. There is acknowledgment of confusion regarding the reference points used for the CoM, and some participants are exploring different notations to aid their understanding.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the information they can share or the methods they can use. There is an emphasis on understanding the geometric relationships involved in the problem.

member 731016
Homework Statement
Please see below
Relevant Equations
Please see below
For part(a),
1675366620399.png

The solution is,
1675370648471.png

However, I made a mistake somewhere in my working below and I'm not sure what it is. Does anybody please know? Thank you!

Here is a not too scale diagram at the moment of the collision,
1675366935512.png

## \vec L = \vec r \times \vec p ##
## \vec L = -y_{com}\hat j \times m_1v\hat i ##
## \vec L = y_{com}m_1v\hat k ##
## \vec L = \frac {m_2m_1v(r_1 +r_2)}{m_1 + m_2}\hat k ##
 

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For part (a) please show what the distance ##y_1## from the CoM to the center of puck 1 is and how you got it in symbolic form.
 
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kuruman said:
For part (a) please show what the distance ##y_1## from the CoM to the center of puck 1 is and how you got it in symbolic form.
Thank you for your reply @kuruman!

I assume that the COM of each puck is at the geometric center.

Choosing the center of ##m_1## as the origin where ##y = 0## and let ##r_3## be the vertical distance from ## y = 0## to the COM of ##m_2##.

## y_1 = y_{com} = \frac {m_1(0) + m_2r_3} {m_1 + m_2} ##

## y_1 = \frac {m_2(r_1 + r_2)} {m_1 + m_2} ##

Then substituting in values,

## y_1 = \frac {0.12(0.1)} {0.2} ##
## y_1 = 0.06 m ##

Also please see post #1, I missed some of the notations so I have edited it.

Many thanks!
 
Thank you for your help @kuruman! I see now how they got their answer. I think I got confused because the solutions calculated the ##y_{com}## from a different point. Good idea to use ##y_1## notation for calculations of CoM with respect to different origins!Many thanks!
 

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