(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

In the field of a point charge over a plane, if you follow a field line that starts at the point charge in a horizontal direction, that is, parallel to the plane, where does it meet the surface of the conductor?

2. Relevant equations

The problem 'hint' is "You'll need Gauss' law and a simple integration."

3. The attempt at a solution

The electric field on the surface of the conductor at a radius R=[tex]\sqrt{r^{2}+h^{2}}[/tex] (h is the height of the pt charge, r is the x component of the radius on the plane), the Electric field due to the point charge is:

E=[tex]\frac{-2Qh}{(r^{2}+h^{2})^{3/2}}[/tex]. This is given in the book.

I have no idea where to start...

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# Homework Help: Where does a field line meet the surface of the conductor?

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