Where Does a Stuffed Animal Land When Dropped from a Ferris Wheel?

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SUMMARY

The discussion centers on calculating the landing point of a stuffed animal dropped from a Ferris wheel with a radius of 5.00 m, completing one revolution every 31.0 seconds. The velocity of the rider at the top of the Ferris wheel is determined to be 1.01 m/s. To find where the stuffed animal lands, one must calculate the time it takes to fall to the ground from a height of 6.75 m (5.00 m radius plus 1.75 m base height) and then use this time to determine the horizontal distance traveled during the fall.

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Fairgoers ride a Ferris wheel with a radius of 5.00 m . The wheel completes one revolution every 31.0 s
If a rider accidentally drops a stuffed animal at the top of the wheel, where does it land relative to the base of the ride? (Note: The bottom of the wheel is 1.75 m above the ground.)

okay so I got that velocity which is 1.01 m/s of the rider on the ferris wheel but I really don't know where to go from there...any suggestions? It seems simple but I am stumped!
 
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Find the time taken for the stuffed animal to reach the ground. Use this time to find where the base will be when the object has landed.
 

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