Ferris Wheel Acceleration Calculation

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SUMMARY

The discussion focuses on calculating the total acceleration of a passenger on a Ferris wheel with a radius of 9.7 meters, completing one revolution every 39 seconds. The Ferris wheel begins to decelerate at a rate of 0.19 rad/s² when the passenger is at the top. To find the total acceleration, both radial and tangential components must be considered, utilizing the equations for centripetal acceleration (acp = v²/r) and angular velocity (ω²r).

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  • Understanding of circular motion concepts
  • Familiarity with angular velocity and acceleration
  • Knowledge of centripetal acceleration equations
  • Basic algebra for solving equations
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  • Calculate angular velocity using the formula ω = 2π/T, where T is the period of rotation.
  • Learn how to derive radial acceleration using acp = ω²r.
  • Study the relationship between tangential acceleration and angular deceleration.
  • Explore examples of total acceleration in circular motion scenarios.
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canadiankid
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Homework Statement


A Ferris wheel with a radius of 9.7m rotates at a constant rate, completing one revolution every 39s.
Suppose the Ferris wheel begins to decelerate at the rate of 0.19rad/s^2 when the passenger is at the top of the wheel.

Find the magnitude of the passenger's acceleration at that time.

Homework Equations


acp=v2/r=ω2r


The Attempt at a Solution


I don't understand the time they want me to use or where to start.
 
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canadiankid said:
I don't understand the time they want me to use or where to start.
They want the passenger's total acceleration when he's at the top of the wheel. You'll need to find the radial and tangential components.
 

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