The discussion clarifies that during nuclear fission, the mass of the products is actually lower than the mass of the original nuclei, contrary to initial assumptions. The reaction example provided is n + U-235 -> 3n + Ba-141 + Kr-92, which illustrates that the total mass of the products is less than that of the reactants. This mass difference is accounted for by the energy released, as described by Einstein's equation E=mc². Therefore, the misconception that the mass of the products is greater is corrected through proper mass counting.
PREREQUISITESStudents of nuclear physics, educators in science, and professionals in nuclear energy sectors will benefit from this discussion, particularly those seeking to understand mass-energy relationships in nuclear reactions.
It isn't. It's lower. Try counting masses in e.g.:Ciaran H said:why is the mass of the products (the two new nuclei and fission neutrons) greater than the mass of the original nuclei?