Where Does the Sign of n Matter in Palka's Examples?

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SUMMARY

The discussion centers on the relevance of the sign of n in Bruce P. Palka's "An Introduction to Complex Function Theory," specifically in Chapter III, Section 1.2, which covers differentiation rules. Participants highlight that in Example 1.1, the assumption of n being positive is crucial because it leads to a finite series, while for negative n, the powers of z do not converge to zero, resulting in an infinite series. Similarly, in Example 1.2, the negative value of n necessitates a different proof approach due to the implications on convergence. The consensus is that Palka's examples require distinct handling based on the sign of n to avoid complications with infinite series.

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I am reading Bruce P. Palka's book: An Introduction to Complex Function Theory ...

I am focused on Chapter III: Analytic Functions, Section 1.2 Differentiation Rules ...

I need help with some aspects of Examples 1.1 and 1.2, Section 1.2, Chapter III ...

Examples 1.1 and 1.2, Section 1.2, Chapter III read as follows:
View attachment 9334
My questions regarding the above two examples from Palka are as follows:Question 1

Can someone please explain where in the calculations of Example 1.1 does the assumption of n being positive becomes relevant ...

I am puzzled because it appears that each of the steps of the calculation are true whether n is positive or negative ...

Question 2

Can someone please explain where in the calculations of Example 1.2 does the assumption of n being negative becomes relevant ...

I am puzzled because it appears that each of the steps of the argument/calculation are true whether n is positive or negative ...Hope someone can help ...

Help will be much appreciated ...

Peter
 

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In z^n- z_0^n= (z- z_0)(z^{n-1}+ z_0z^{n-2}+ \cdot\cdot\cdot+ z_0^{n-2}z+ z_0^{n-1}), with n positive, powers of z are decreasing and eventually become 0 in the z_0^{n-1} term. If n is negative powers of z decreasing become more negative so do not eventually become 0. We get a infinite series. It might well be true that you could prove the desired statement using infinite series but that Palka wants to avoid the additional complications of infinite series (which may not have been introduced at this point). And since the proof given is only for n positive, a separate proof has to be given for n negative.
 
HallsofIvy said:
In z^n- z_0^n= (z- z_0)(z^{n-1}+ z_0z^{n-2}+ \cdot\cdot\cdot+ z_0^{n-2}z+ z_0^{n-1}), with n positive, powers of z are decreasing and eventually become 0 in the z_0^{n-1} term. If n is negative powers of z decreasing become more negative so do not eventually become 0. We get a infinite series. It might well be true that you could prove the desired statement using infinite series but that Palka wants to avoid the additional complications of infinite series (which may not have been introduced at this point). And since the proof given is only for n positive, a separate proof has to be given for n negative.

Thanks for the help, HallsofIvy ...

Peter
 

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