Where Does the Vector Come to Rest Given u and a?

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SUMMARY

The discussion centers on determining the position vector (r) when a given velocity vector (u) comes to rest under constant acceleration (a). The initial velocity is defined as u = -14i - 7j, and the acceleration is a = 6i + 3j. To find the position vector when the velocity is zero, one must utilize the relationships between position, velocity, and acceleration, specifically through kinematic equations. The participant struggled with differentiation and understanding the necessary calculus concepts to solve the problem.

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Homework Statement



find the position (r) when the vector comes to rest.

Homework Equations



initially velocity = 'u', acceleration = a
u= -14i-7j
a= 6i+3j

The Attempt at a Solution



hey guys I am new at this so i didnt know how to post it but some help would be great :)
i tried solving it for when v=0 but i didnt know how, neither could i differentiate it :/
 
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thunderflap said:

Homework Statement



find the position (r) when the vector comes to rest.

Homework Equations



initially velocity = 'u', acceleration = a
u= -14i-7j
a= 6i+3j

The Attempt at a Solution



hey guys I am new at this so i didnt know how to post it but some help would be great :)
i tried solving it for when v=0 but i didnt know how, neither could i differentiate it :/

Hi thunderflap, Welcome to Physics Forums.

Were you given an initial position vector too?

What are the (calculus) relationships between position, velocity, and acceleration? If this had been a problem not using vectors and you were given separate x and y components for acceleration and initial velocity, what would your approach be? What kinematic formulas might you employ?
 
Last edited:

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