1. The problem statement, all variables and given/known data A 2 kg mass with initial velocity v = (5i + 7j) collides perfectly elastically with a 3 kg mass with initial velocity v = (-1i -3j) After the collision, the 2kg mass has a speed of √50 m/s and the 3 kg mass is traveling at an angle of 329.77Θ as measured from the positive x axis. Determine the speed of the 3 kg mass after the collision and the angle of the 2 kg mass after the collision (as measured from the positive x axis). i and j are the x and y axis respectively. 2. Relevant equations P = MV KE = 0.5MV^2 A*B = XYCosΘ 3. The attempt at a solution Initial: KEm1 = 0.5(2)(5i + 7j)^2 KEm2 = 0.5(3(-1i - 3j)^2 Pm1 = 2(5i + 7j) Pm2 = 3(-1i - 3j) Final: KEm1 = 0.5(2)(√50)^2 Cosø KEm2 = 0.5(3)V^2 Cos(329.77) Pm1 = 2(√50) Pm2 = 3V I know that initial momentum and KE of the system should equal the final momentum and KE of the system, but I can't figure out how to set that up with a 2 dimensional collision. Normally it would be KEi = KEf and Pi = Pf, but with i and j coordinators I can't figure out how to make that work. Should KE and P for the y coordinate and the x coordinate be calculated separately?