Where is the 5.50 N force applied along the meter stick?

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SUMMARY

The discussion centers on a physics problem involving a meter stick pinned at one end, with two forces applied to achieve zero net torque. A force of 1.90 N is applied perpendicularly at the free end, while a 5.50 N force is applied at a 27-degree angle. The solution requires calculating the position along the stick where the 5.50 N force is applied to maintain equilibrium. The user successfully resolved the problem independently, indicating a clear understanding of torque and force application.

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One end of a meter stick is pinned to a table, so the stick can rotate freely in a plane parallel to the tabletop. Two forces, both parallel to the tabletop, are applied to the stick in such a way that the net torque is zero. One force has a magnitude of 1.90 N and is applied perpendicular to the length of the stick at the free end. The other force has a magnitude of 5.50 N and acts at a 27 degree angle with respect to the length of the stick. Where along the stick is the 5.50 N force apllied? Express this distance with respect to the end that is pinned.
 
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sorry about that, but I figured out the problem on my own and the other question i had too.
 

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