Where is the recurrence stable in the (n,x) plane for increasing n?

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SUMMARY

The discussion centers on identifying the recurrence stability in the (n,x) plane for increasing n, specifically through the equation $$E_{n+1}(x) = \frac{1}{n}\left( \exp(-x)-xE_n(x)\right)$$ where $$E_n\equiv \int_1^\infty \frac{\exp(-xt)}{t^n}\,dt$$. The user expresses confusion regarding the term "stable" and seeks clarification on its meaning in this mathematical context. A proposed solution involves writing code to compute the difference between $$E_n$$ and $$E_{n+1}$$ to determine when this difference approaches zero, indicating stability.

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Homework Statement


In the ##(n,x)## plane, where is the recurrence stable for increasing ##n##?

$$E_{n+1}(x) = \frac{1}{n}\left( \exp(-x)-xE_n(x)\right):E_n\equiv \int_1^\infty \frac{\exp(-xt)}{t^n}\,dt$$
and ##n\in \mathbb{N},\:x\geq0##.

Homework Equations


Nothing comes to mind.

The Attempt at a Solution


I really don't know how to proceed because I don't understand what "stable" means in this context. I was hoping someone with more experience could help me out. I typically have an approach when posting here, but this time I'm stuck.

Nothing on this topic is in the book we're using, so I'm stuck.
 
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"Stable" usually means unchanging, so my best guess in this problem is that for what x will ##E_n = E_{n + 1}##?
 
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Ohhhh gotcha! And thanks! So my thoughts are to write a code that computes the difference between ##E_n## and ##E_{n+1}## and see when that difference is very small. What do you think?
 

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