A very weird improper integral on ^n

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SUMMARY

The discussion focuses on verifying the improper integral \(\int_{\mathbb{R}^n} \exp\left(-\frac{\lambda}{2} \langle Ax, x \rangle - i \langle x, \zeta \rangle\right) dx\) and its equivalence to \((\frac{2\pi}{\lambda})^{\frac{1}{2}} (\det A)^{-\frac{1}{2}} \exp\left(-\frac{1}{2\lambda} \langle A^{-1}\zeta, \zeta \rangle\right)\). The matrix \(A\) is a symmetric matrix of complex numbers, and the condition \(\langle \text{Re} A x, x \rangle > 0\) ensures positive definiteness. The transformation \(x = C y\), where \(C\) belongs to \(SO(n)\), simplifies the integral by diagonalizing \(A\) and allows the application of Fubini's Theorem for iterated integration.

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Homework Statement


Verify that \int_{ℝ^n}exp(-\frac{λ}{2} \langle Ax, x \rangle-i \langle x,ζ \rangle )dx=(\frac{2\pi}{λ})^{\frac{1}{2}}(detA)^{-\frac{1}{2}}exp(-\frac{1}{2λ} \langle A^{-1}ζ, ζ \rangle ) where A is a symmetric matrix of complex numbers and <ReA x, x> is positive definite, and λ is a positive constant. ζ is a vector in ℝ^n

Homework Equations


Fubini's Theorem?

The Attempt at a Solution


The question is a lot easier if A is brought to diagonal form, so it is reasonable to make a change of variable that x= C y where C belongs to SO(n) such that C^-1 A C = B is diagonal. Since this change of variables means only geometrically a rotation of the R^n plane it should not change the range of values for integrating(still from -∞ to ∞). After this transformation we should be able to apply Fubini's Theorem and perform an iterated integration. But in the exponential function exp(-i\langle Cy, ζ \rangle) is still left to be dealt with and it doesn't come any where close that it could be of the form exp(-\frac{1}{2λ} \langle A^{-1}ζ, ζ \rangle) after integration as the answer suggests.. right now I'm trully stuck here.. Thanks for any help in advance!
 
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det A here means |det A| exp(i \sum_0^n{arg w_i}) where w is the eigenvalue of A.
This question even takes 20 minutes to type.. or I really suck at latex..
 

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