Which angle do I need for the torque?

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SUMMARY

The discussion focuses on determining the relevant angles for calculating torque in a cable system with a hinge as the axis of rotation. The torque equation is defined as Torque = Force * radius, where the radius is the perpendicular distance from the axis of rotation to the line of action of the force. Participants emphasize the importance of using the correct angle, either phi or theta, and suggest leveraging similar triangles to compute the necessary dimensions for torque calculations. The conversation highlights the relationship between angles and the geometry of the setup, specifically using right triangles to derive the required values.

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  • Understanding of torque and its equation: Torque = Force * radius
  • Knowledge of trigonometric functions, particularly sine
  • Familiarity with right triangles and the concept of similar triangles
  • Basic geometry skills to analyze angles and lengths in diagrams
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Homework Statement


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Which angle is relevant to the torque of the cable with the hinge as the axis of rotation? Where is the radius used in the Torque equation?


Homework Equations


Torque = Force * radius


The Attempt at a Solution


I don't know which one to use, they are both angles created by the axis and the cable. And as for the radius, I think it is the red line I drew perpendicular to the cable.
 
Last edited:
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The torque of the cable on the rod will be equal to the tension in the cable times the sine of \varphi times dh
 
sine is opposite over hypotenuse so I get:

2D9AB.png


Bu we don't know what 'x' is. How do you solve for it in terms of d_v or d_h or L?
 
Since phi and theta add up to a right angle you can use either one, provided you use it in the right way.
In the diagram, you know dh and dv, so you can compute the hypoteneuse. You just need to find the length of the red line. Can you spot some similar triangles?
 
I'm not good with finding similar triangles. I can't see any here no matter how I look at it. But is the perpendicular line I drew a bisector of the cable length?
 
PhizKid said:
I'm not good with finding similar triangles. I can't see any here no matter how I look at it. But is the perpendicular line I drew a bisector of the cable length?
No.
All you need for two triangles to be similar is two angles that match. Often, one of those angles doesn't merely match in size, it is actually the same angle in the picture.
In the present case, all you have are right angles, the angle the cable makes to the vertical, and simple sums and differences of those.
 
Assuming you know dv and dh, use triangle ABC to find angle θ1 or θ2. Then you can use a smaller triangle to find the lever arm for the tension.
[EDIT: This is just a suggestion if you are having trouble seeing haruspex's similar triangles. I'm not saying that my suggestion is a better approach.]
 

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