Which angle do I need for the torque?

  • Thread starter Thread starter PhizKid
  • Start date Start date
  • Tags Tags
    Angle Torque
Click For Summary

Homework Help Overview

The discussion revolves around determining the relevant angle for calculating torque in a scenario involving a cable and a hinge as the axis of rotation. Participants are exploring the relationship between angles, the radius in the torque equation, and the geometry of the situation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to identify which angle is relevant for torque calculation and how the radius is defined in this context. There are questions about the relationship between angles and the geometry of the setup, including the use of sine in the torque equation.

Discussion Status

The discussion is active, with various interpretations of the geometry being explored. Some participants have offered suggestions regarding the use of similar triangles and the relationships between angles, while others express uncertainty about these concepts.

Contextual Notes

There are indications of missing information regarding specific lengths and angles, as well as the challenge of visualizing similar triangles in the given setup. Participants are navigating through these constraints while adhering to homework guidelines.

PhizKid
Messages
477
Reaction score
2

Homework Statement


CzxAd.png


Which angle is relevant to the torque of the cable with the hinge as the axis of rotation? Where is the radius used in the Torque equation?


Homework Equations


Torque = Force * radius


The Attempt at a Solution


I don't know which one to use, they are both angles created by the axis and the cable. And as for the radius, I think it is the red line I drew perpendicular to the cable.
 
Last edited:
Physics news on Phys.org
The torque of the cable on the rod will be equal to the tension in the cable times the sine of \varphi times dh
 
sine is opposite over hypotenuse so I get:

2D9AB.png


Bu we don't know what 'x' is. How do you solve for it in terms of d_v or d_h or L?
 
Since phi and theta add up to a right angle you can use either one, provided you use it in the right way.
In the diagram, you know dh and dv, so you can compute the hypoteneuse. You just need to find the length of the red line. Can you spot some similar triangles?
 
I'm not good with finding similar triangles. I can't see any here no matter how I look at it. But is the perpendicular line I drew a bisector of the cable length?
 
PhizKid said:
I'm not good with finding similar triangles. I can't see any here no matter how I look at it. But is the perpendicular line I drew a bisector of the cable length?
No.
All you need for two triangles to be similar is two angles that match. Often, one of those angles doesn't merely match in size, it is actually the same angle in the picture.
In the present case, all you have are right angles, the angle the cable makes to the vertical, and simple sums and differences of those.
 
Assuming you know dv and dh, use triangle ABC to find angle θ1 or θ2. Then you can use a smaller triangle to find the lever arm for the tension.
[EDIT: This is just a suggestion if you are having trouble seeing haruspex's similar triangles. I'm not saying that my suggestion is a better approach.]
 

Attachments

  • Torque problem.jpg
    Torque problem.jpg
    20.2 KB · Views: 467
Last edited:

Similar threads

  • · Replies 42 ·
2
Replies
42
Views
4K
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 10 ·
Replies
10
Views
6K