Which Bead Reaches the Bottom First?

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SUMMARY

The discussion centers on a physics problem involving two beads sliding down rods of different lengths and angles. The red bead, descending a vertical rod of length D, follows the equation D = 0.5 * g * t², while the blue bead, descending a rod of length L at an angle θ, is governed by the equations a_b = g * sin(θ) and L = 0.5 * a_b * t². The conclusion reached is that both beads will reach the bottom simultaneously, which can be mathematically demonstrated by substituting the equations for the blue bead into the equation for the red bead, confirming that their descent times are equal.

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tacutamon
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Homework Statement


Two thin rods are fastened to the inside of a circular ring as shown in the figure below. One rod of length D is vertical, and the other of length L makes an angle θ with the horizontal. The two rods and the ring lie in a vertical plane. Two small beads are free to slide without friction along the rods.

2-p-069.gif


If the two beads are released from rest simultaneously from the positions shown, use your intuition and guess which bead reaches the bottom first.

Homework Equations


Equations for Red Ball:
(1) D = .5*g*t^{2}

Equations for Blue Ball:
(2) a_{b} = g*sin(θ)

(3) L = .5*a_{b}*t^{2}

(4) L = D*sin(θ)


The Attempt at a Solution


The correct answer is that they will hit the ground at the same time. I am still curious in how I would explain this mathematically, rather than intuitively as the question states. I believe I have all the necessary equations to do so, but I am not sure how to compare them to show this. Would I show that subbing in equation 4 and 2 into equation 3 would give me equation 1?

Thanks so much for your help!
 
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Hello, tacutamon and welcome to PF!

tacutamon said:

Homework Equations


Equations for Red Ball:
(1) D = .5*g*t^{2}

Equations for Blue Ball:
(2) a_{b} = g*sin(θ)

(3) L = .5*a_{b}*t^{2}

(4) L = D*sin(θ)

Would I show that subbing in equation 4 and 2 into equation 3 would give me equation 1?

Yes, that would work. Or, you could solve (1) for the red ball's time and solve (3) for the blue ball's time and try to show the times are equal.
 
Thanks so much! That really clears up a lot.
 

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