Which Force Achieves Rotational Equilibrium for a Pivoted Bar?

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SUMMARY

The discussion centers on determining which force achieves rotational equilibrium for a pivoted bar subjected to a 200N force. The key equation is Torque = Force x Distance, with the condition that the sum of torques must equal zero (∑Torque= 0). The consensus is that the problem lacks sufficient information regarding the distances at which the forces act, leading to the conclusion that option (e) "none of these" is the most appropriate answer due to the assumption of equal spacing between points and neglecting the weight of the bar.

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Soniteflash
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Homework Statement


The lightweight pivoted bar in the figure will be in rotational equilibrium when a 200N force acts
rjmepv.jpg
(a) down at D
(b) up at B
(c) down at E or up at C
(d) up at C only
(e) none of these

Homework Equations


Torque = Force x Distance
∑Torque= 0 for rotational equilibrium

The Attempt at a Solution


I know that in order for the bar to be in rotational equilibrium, the sum of torques must equal zero. My problem is that the problem does not give me information about the distance the forces act. In my opinion the problem does not give me enough information to answer the problem correctly.

Therefore I chose e which I am not sure about either.
 
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It looks to me as if you are supposed to assume the points are equally spaced, AB=BC=CD=DE=EF=FG
and to neglect the weight of the "light" bar.
 
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