- #1
Sanchayan Dutta
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My Approach is shown in the picture.
Which method is correct for this problem involving motion of
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Homework Help Overview
The discussion revolves around a problem involving the motion of charged particles and the forces acting on them, particularly focusing on electric forces and tension in a string. Participants are exploring the dynamics of a particle in motion under the influence of these forces.
Discussion Character
- Exploratory, Assumption checking, Problem interpretation
Approaches and Questions Raised
- Participants present various methods for analyzing the forces on a charged particle, questioning the direction of electric forces and the representation of the problem setup. There are discussions about the conditions at the highest and lowest points of motion, as well as the contributions to tension in the string.
Discussion Status
The discussion is active with multiple interpretations being explored. Some participants are questioning the accuracy of the diagrams and assumptions made regarding the forces acting on the particle. Guidance has been offered regarding the contributions to tension and the conditions under which it may be zero.
Contextual Notes
There are indications of confusion regarding the positions of the charged particle and the corresponding forces, as well as the implications of these positions on the overall analysis. Participants are also reflecting on the correctness of their methods and the assumptions underlying their approaches.
My Approach is shown in the picture.
- #2
nasu
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It may be that none of the answers are right.
For the first method, are the two electric forces on Q in the same direction, when Q is on top?
For the first method, are the two electric forces on Q in the same direction, when Q is on top?
- #3
Sanchayan Dutta
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yes they are in same direction.nasu said:
- #4
nasu
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Do you think that your diagram represents the situation described in the problem?
I mean "particle B at the highest point".
I mean "particle B at the highest point".
- #5
J Hann
- 264
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The tension in the string is zero at the top for the given conditions.
Add the contributions to the tension (centripetal force, weight of the mass, and the two electrical forces
such that the tension is zero.
It might be easier to think of the acceleration at the top (m v^2 / R = weight + the two electrical forces)
Add the contributions to the tension (centripetal force, weight of the mass, and the two electrical forces
such that the tension is zero.
It might be easier to think of the acceleration at the top (m v^2 / R = weight + the two electrical forces)
- #6
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They are not. Maybe, as nasu wonders, you are taking Q at the lowest point instead of the highest.Sanchayan Dutta said:
In your method 2, you write that the tension is minimum when Q is at the bottom. What makes you think that?
Seems to me that is exactly Sanchayan's method 1, but the execution was lacking.J Hann said:
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