Which molecule has two lone pairs on the central atom?

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SUMMARY

The molecule with two lone pairs on the central atom is XeF4. PCl3 has only one lone pair, while ICl4^+ and CH3I do not meet the criteria. The correct interpretation of "two lone pairs" refers to four total unshared electrons, which applies to XeF4. The bonding in these molecules involves spd hybridization, particularly relevant for XeF4's square planar geometry.

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I have to figure out which has two lone pairs on the central atom between PCl3, ICl4^+, CH3I, XeF4, PCl6^-.

Is it PCl3? I think I did it right but I am not sure.
Thank you.
 
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Think you are correct. The three 3p3 electrons of P should be bonded to the three Cls, each one forming single bonds. That leaves the pair of 3s2 electons unshared. Haven't even looked at the other choices, since I feel PCl3 is the one.

If incorrect, please someone let me know.

Best of luck.

Steve
 
hi Steve, thanks.
I re-checked my answer and realize I think I read the question wrong... Two lone pairs, meaning four all together (I was interpreting it like two, not two pairs) if that makes sense. Then I think it's XeF4.
 
Smith4046 said:
Think you are correct. The three 3p3 electrons of P should be bonded to the three Cls, each one forming single bonds. That leaves the pair of 3s2 electons unshared. Haven't even looked at the other choices, since I feel PCl3 is the one.

If incorrect, please someone let me know.

Best of luck.

Steve

The bonds are not strictly s and p bonds, but rather are spd hybridized.

PCl_{3} has only one lone pair. So, you can rule it out.

Carbon must obey the octet rule, so you can rule out iodomethane.

Try drawing Lewis structures for the other 3. One is square planar (octahedral), thanks to its two lone pairs.
 
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