Which Object Reaches the Bottom First? - Solving a Rotational Dynamics Problem

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SUMMARY

The discussion focuses on the dynamics of a uniform solid cylinder and a uniform cylindrical shell rolling down an incline. Using the conservation of energy equations, the solid cylinder, with a moment of inertia of I=1/2(mr²), is determined to have a greater velocity at the bottom compared to the hollow cylinder, which has a moment of inertia of I=mr². Consequently, the solid cylinder reaches the bottom first, contradicting the initial assumption that both would arrive simultaneously.

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  • Understanding of rotational dynamics and moment of inertia
  • Familiarity with conservation of energy principles
  • Knowledge of rolling motion and the concept of rolling without slipping
  • Basic proficiency in algebra and physics equations
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Homework Statement


A uniform solid cylinder and a uniform cylindrical shell are placed side by side at the top of an incline.If they sre released from rest and roll without slipping,
A)Determine their speeds when they reach the bottom
B)Which objet reaches the bottom first?

Homework Equations


I=mr2 for the cylindrical shell
I=1/2(mr2)
mgyi+1/2(Iw2)+1/2(mv2)=mgyf+1/2(Iw2)+1/2(mv2)



The Attempt at a Solution

I used this conservation of energy equation for each object and got gyi=1/2(r2w2)+1/2(v2) for the hollow cyinder.
then gyi=1/4(r2w2+1/2(v2) for the solid cylinder. since gyi is the same for both i figured that the sollid mass must have a greater velocity and therefore reach the bottom first? Initially i thought they would both have the same velocity and both reach the bottom at the same time. However this result i came up with doesn't quite agree with that.
 
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Thanx, that was perfect:biggrin:
 

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