Which will reach the bottom faster: solid or hollow sphere?

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The discussion centers on the dynamics of a solid sphere versus a hollow sphere rolling down an incline without slipping. Although both spheres have the same mass and radius, their moments of inertia differ, leading to different angular accelerations. The solid sphere, having a lower moment of inertia, accelerates faster than the hollow sphere due to its greater angular acceleration, despite both experiencing the same linear acceleration at their centers of mass. The participants debate the relationship between translational and rotational motion, ultimately concluding that the net forces acting on the spheres differ, affecting their acceleration. The solid sphere will reach the bottom of the incline faster than the hollow sphere.
  • #31
llober said:
I think is better to do an Energy balance...
https://www.physicsforums.com/attachments/104346
But won't mechanical energy change due to friction? just curious
 
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  • #32
Milo Martian said:
But won't mechanical energy change due to friction? just curious
If there's no sliding, there's no loss by friction, because the no sliding translates into speed zero at the contact point, so the "friction force" does not move.
 
  • #33
llober said:
If there's no sliding, there's no loss by friction, because the no sliding translates into speed zero at the contact point, so the "friction force" does not move.
OK
 
  • #34
Milo Martian said:
Okay, i got it .
Fext= mgsinA - f= macm ...(1)
fXR= torque = I X angular acc. = I X acm/R
=> f= Iacm/R2 ...(2)
From (1) and (2) :
macm = mgsinA - Iacm/R2
=> acm= mgsinA/(m + I/R2)
So, since Isolid sphere< Ihollow sphere
Therefore, acm for solid sphere> acm for hollow sphere.
i hope i am right. phew
You got it.
 

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